PHP判断Form表单是否提交
By Symphony - Last updated: Tuesday, May 13, 2008 - Save & Share - Leave a Comment
$submitButtonValue = $_POST['submit_button_name'];
if( "submit" == $submitButtonValue )
{
//执行表单操作
}
else
{
//返回
}
$submitButtonValue = $_POST['submit_button_name'];
if( "submit" == $submitButtonValue )
{
//执行表单操作
}
else
{
//返回
}